javascript - Input an english word, get back an integer -

i work in college radio station, , want way catalogue our physical music numbers. want take artist, release name, , year, , compute 9 digit number.

i have few things coded already.

function bijection(letter) read single character, reference var alpha = ["0","1","2",..."9","a","b",..."x","y","z"], , return index of provided character. so, bijection(c) = 13, example.

function bijection(character){     var alpha = ["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"];     var position = alpha.indexof(character) + 1;     return position; } 

function easyread(string) take string of characters, , remove spaces. so, easyread("two door cinema club") returns twodoorcinemaclub.

function easyread(noun){     var out = noun.split(' ').join('');     return out; } 

function label(number1,number2,number3) take 3 numbers, evaluate each mod 1000, , combine them 9-digit integer. example, label(1001,1002,1003) returns 100200300.

function label(sum1,sum2,year){     var label = 1000000*(sum1%1000) + 1000*(sum2%1000) + year%1000;     return label; 

i want write function called sigma, take string no spaces, break character character, , add indices. so, i'd run string through easyread, plug sigma, refer bijection in iteration on each character in string, , maths return sum of each bijection(character). take whatever sigma outputs, , have input label. i'm lost on how make sigma happen, though. help?

updates:

this got far.

function sigma(noun){    var domain = easyread(noun) //removes spaces input noun    for(let n = 0; n<domain.length; n++) {      //start n = 0, , stop when n incrementally larger length of our spaces-removed string.      let iterative = domain[n]; //not sure bijection(iterative);                                 //tells computer calculate bijection of each character    } //return sum of bijection(iterative), somehow? } 

given pretty new javascript, try best avoid using complex apis.

essentially strip out spaces, have string.replace(...). api takes in regular expression pattern. want /\s/g want "find spaces within string" , 2nd parameter '', replace with ''.

after want loop through each characters in spaceless string value, simple for-loop , on each loop call bijection() function.

consider code below.

example:

"use strict";      function bijection(char) {        // assuming bijection fn        console.log("converting character: " + char + " value..." );        return 10; // assuming every character value of 10.      }        let test = "one may  have  spaces ";      let nospace = test.replace(/\s/g, "");      let totalvalue = 0;        for(let n = 0; n < nospace.length; n++) {        let char = nospace[n];        totalvalue += bijection(char);      }        console.log("total value => " + totalvalue);