python 2.7 - Find a value based on a matching word and store it -

i new python, , im trying feel language

i have file called lion.txt has text:

the lion (panthera leo) 1 of big cats in genus panthera , member of family felidae. commonly used term african lion collectively denotes several subspecies in africa. males exceeding=250/12 kg (550 lb) in weight,[4].

what want program search keyword exceeding , write value 250 file called searched.txt. @ best possible store variable , print text file?

this have far:

import os import re  os.chdir("c:\python 2016 training\lionfolder") f = open("lion.txt", "r") w = open("searched.txt", "w")  k = [] #figured dictionary best way deal this?  line in f:     if re.match('(.*)exceeding(.*)',  line):     w.write(k[1] = "line") 

is im asking possible python?

thank in advance

regards, kevin.

not bad first attempt. you're close working solution, missing critical parts. try this:

import os import re  f = open('lion.txt', 'r') w = open('searched.txt', 'w')  line in f:     match = re.search('exceeding\=(\d+)', line)     if match:         w.write(match.group(1))  w.close() f.close() 

there better ways of doing this, have tried stay close original code possible, don't lost.