python - Read Textfile Write new CSV file -

currently have following code prints desired lines .kap file.

f = open('120301.kap') line in f:     if line.startswith('ply'):        print line 

this results in following output

ply/1,48.107478621032,-69.733975000000  ply/2,48.163516399836,-70.032838888053  ply/3,48.270000002883,-70.032838888053  ply/4,48.270000002883,-69.712824977522  ply/5,48.192379262383,-69.711801581207  ply/6,48.191666671083,-69.532840015422  ply/7,48.033358898628,-69.532840015422  ply/8,48.033359033880,-69.733975000000  ply/9,48.107478621032,-69.733975000000 

my goal not have print these lines. i'd have csv file created named 120301.csv coordinates in there own columns (leaving ply/# behind). simple enough? i've been trying different import csv functions awhile now. can't seem anywhere.

step step, since looks you're struggling basics:

f_in = open("120301.kap") f_out = open("outfile.csv", "w")  line in f_in:     if line.startswith("ply"):  # copy line new file         # split columns, ignoring first 1 ("ply/x")         _, col1, col2 = line.split(",")         # format output         outstring = col1 + "," + col2 + "\n"         # , write out         f_out.write(outstring)  f_in.close() f_out.close()  # bad practice, i'll 

of course not best way this. there's reason have things csv module.

import csv  open("120301.kap") inf, open("outfile.csv", "wb") outf:     reader = csv.reader(inf)     writer = csv.writer(outf)     row in reader:         # if first cell of row starts "ply"...         if row[0].startswith("ply"):             # write out row, ignoring first column             writer.writerow(row[1:]) # opening files using "with" context managers means don't have # remember close them when you're done them.