<?php session_start(); include_once "dbconnect.php"; if(isset($_post['btn_up'])){ $email = $_post['sn']; if($email == ''){ echo 'there error'; }else{ echo $email; echo "something happened"; } } var_dump($email); ?> <!doctype html> <html> <head> <title> admin </title> </head> <body> <form method='post'> <label for="select">school name</label> <select name="sn"> <option value="-" selected data-default>-</option> <?php $query = mysql_query("select * users school = 'sn'"); while($rowtwo = mysql_fetch_array($query)){ ?> <option value="<?php echo $rowtwo['email']; ?>"><?php echo $rowtwo['email']; ?></option> <?php } ?> </select> <button type="submit" name='btn_up'>up</button> </form> </body> </html> i'm working on making admin page, section of code. on viewers side looks right, when select value drop down , press "btn_up", code doesn't save user email in variable $email, thats why checks if blank because telling me nothing being saved value. how can have save whatever value selected drop down list? var_dump() gave me error
there errorstring(0) ""
<script src="jquery-3.1.0.js"></script> <script> $(function () { $('#selectnumber').change(function(){ alert('.val() = ' + $('#selectnumber').val() + ' , html() = ' + $('#selectnumber option:selected').html() + ' , .text() = ' + $('#selectnumber option:selected').text()); }) }); </script> <select id="selectnumber"> <option value="1">one</option> <option value="2">two</option> <option value="3">three</option> <option value="4">four</option> </select> 
thanks... :)
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