Python program to check matching of simple parentheses -

i python newbie , came across exercise of checking whether or not simple brackets "(", ")" in given string matched evenly.

i have seen examples here using stack command havent encountered yet.so attempted different approach. can tell me going wrong?

def matched(str): ope = [] clo = [] in range(0,len(str)):     l = str[i]     if l == "(":         ope = ope + ["("]     else:         if l == ")":             clo = clo  + [")"]         else:             return(ope, clo) if len(ope)==len(clo):     return true else:     return false 

the idea pile "(" , ")" 2 separate lists , compare length of lists. had version had appended lists ope , clo relevant held either ( or ) respectively.

thanks time!

a more elegant way below. cleans loop , replaces lists simple counter variable. returns false if counter drops below 0 matched(")(") return false.

def matched(str):     count = 0     in str:         if == "(":             count += 1         elif == ")":             count -= 1         if count < 0:             return false     return count == 0